List Collection componets based object mapping in Hibernate 4.x

In Hibernate you can also map a collection of component based objects by making object Embeddable  . like in following example we have Product and one product can have multiple image and image can have further its attribute like image name ,width length . so we put all image object in collection and map to it a single product object .

here we have

Product.java

package in.jk.list.component.maping;

import java.util.List;

 

import javax.persistence.CollectionTable;

import javax.persistence.ElementCollection;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.OrderColumn;
import javax.persistence.Table;

@Entity

@Table(name="Products")

public class Product {

 

@Id

 

private int productId;

private String productName;
private String price;

@ElementCollection
@CollectionTable(name="Prodcut_Images")
@OrderColumn(name="product_image_index")
private List<ProductImage> productImageList;

public int getProductId() {
return productId;
}

public void setProductId(int productId) {

this.productId = productId;

}

public String getProductName() {

return productName;
}

public void setProductName(String productName) {

this.productName = productName;
}

public String getPrice() {

return price;
}

public void setPrice(String price) {

this.price = price;
}

public List<ProductImage> getProductImageList() {

return productImageList;
}

public void setProductImageList(List<ProductImage> productImageList) {

this.productImageList = productImageList;

}
}


ProductImage.java

package in.jk.list.component.maping;

import javax.persistence.Embeddable;

 

@Embeddable

public class ProductImage {

 

private String imageName;

private int length;
private int width;

public String getImageName() {
return imageName;
}

public void setImageName(String imageName) {

this.imageName = imageName;
}

public int getLength() {

eturn length;
}

public void setLength(int length) {

this.length = length;

}

public int getWidth() {

return width;
}

public void setWidth(int width) {

this.width = width;


}
}

Hibernate.cfg.xml

<?xml version = "1.0" encoding = "utf-8"?>

<!DOCTYPE hibernate-configuration SYSTEM

"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">

<hibernate-configuration>

<session-factory>

<property name="hibernate.show_sql">true</property>

<property name="hbm2ddl.auto">update</property>
<property name="hibernate.dialect">org.hibernate.dialect.ProgressDialect</property>
<property name="hibernate.connection.driver_class">org.postgresql.Driver</property>
<!-- Assume hibernate is the database name -->

<property name="hibernate.connection.url">jdbc:postgresql://localhost/hibernate</property>

<property name="hibernate.connection.username">postgres</property>
<property name="hibernate.connection.password">postgres</property>
<mapping class="in.jk.list.component.maping.Product" />

</session-factory>

</hibernate-configuration>

 

HibernateTest .java

package in.jk.list.component.maping;

 

import java.util.ArrayList;

import java.util.List;

import org.hibernate.Session;

import org.hibernate.SessionFactory;
import org.hibernate.Transaction;
import org.hibernate.cfg.Configuration;
import org.hibernate.service.ServiceRegistry;
import org.hibernate.service.ServiceRegistryBuilder;

public class HibernateTest {

public static void main(String[] args) {

Configuration configuration = new Configuration();configuration.configure("hibernate.cfg.xml")

ServiceRegistry serviceRegistry = new ServiceRegistryBuilder().applySettings(configuration.getProperties())

.buildServiceRegistry();

SessionFactory sessionFactory = configuration.buildSessionFactory(serviceRegistry);

 

Session session = sessionFactory.openSession();

Transaction transaction = session.beginTransaction();


 

Product product1 = new Product();

product1.setProductId(1);

product1.setProductName("Mobile");
product1.setPrice("20000");

ProductImage productImage1 = new ProductImage();

productImage1.setImageName("Mob1");

productImage1.setLength(12);
productImage1.setWidth(58);

ProductImage productImage2 = new ProductImage();

 

productImage2.setImageName("Mob2");

productImage2.setLength(18);
productImage2.setWidth(48);

ProductImage productImage3 = new ProductImage();

productImage3.setImageName("Mob3");

productImage3.setLength(23);
productImage3.setWidth(89);

List<ProductImage> imageList = new ArrayList<ProductImage>();

imageList.add(productImage1);

imageList.add(productImage2);
mageList.add(productImage3);
product1.setProductImageList(imageList);

session.persist(product1);

transaction.commit();

 

session.flush();

session.close();
System.out.println("Saved.............");
 

 

}
}
 In Database Products table data looks like this .......
 

 
 
 
Product_image table with Prodcuct Image Data

 

 

 

       

 

 

 

 
 

  

 

 

 

 

 

 

 

 

　

　

 

 

 

 

       

 

 

       

 

       

 

 

 

 

       

       

 

       

 

 

       

 

 

       

 

 

 

 

 

 

 

 

 

 

 

　

 

 

 

 

Map type Collection maping by hibernate 4.x

In Java java.util.Map is Hashtable based collection allow store key/value pair

suppose we have following Polyglot programmer can have do  programing  in multiple language .they can have  knowledge of multiple programing  language .
we can create a map of programing language
we can  map one polyglot programmer class object with multiple programing languages map   like following .

PolyglotProgramer .java

package in.jk.set.maping;

import java.util.Map;
import javax.persistence.CollectionTable;

mport javax.persistence.Column;
import javax.persistence.ElementCollection;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.MapKeyColumn;
import javax.persistence.Table

@Entity

@Table(name="polyglot_programer_map")

public class PolyglotProgramer {

@Id

private String developerId;
private String developerName;
private String companyName;

@ElementCollection

@CollectionTable(name="Programing_langs" ); // table for saving the map data
@MapKeyColumn(name="Language_key")  // for saving map key
@Column(name="language_name")              // for saving map key value
private Map<String,String> programingLanguages;
 

 

 

  

public String getDeveloperId() {

return developerId;
}

public void setDeveloperId(String developerId) {

 

this.developerId = developerId;

 

}
 
 

public String getDeveloperName() {

return developerName;
}
public void setDeveloperName(String developerName) {

this.developerName = developerName;

 

}

public String getCompanyName() {

return companyName;

 

}

public void setCompanyName(String companyName) {

this.companyName = companyName;

 

}

public Map<String,String> getProgramingLanguages() {

return programingLanguages;

 

}

public void setProgramingLanguages(Map<String,String> programingLanguages) {

this.programingLanguages = programingLanguages;

 

}

 

HibernateTest.java Class

 

  

package in.jk.list.maping;

import java.util.ArrayList;

import java.util.List;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.Transaction;

import org.hibernate.cfg.Configuration;

import org.hibernate.service.ServiceRegistry;

import org.hibernate.service.ServiceRegistryBuilder;

public class HibernateTest {
 
public static void main(String[] args) {
Configuration configuration = new Configuration();

configuration.configure("hibernate.cfg.xml");
ServiceRegistry serviceRegistry = new ServiceRegistryBuilder().applySettings(configuration.getProperties())

.buildServiceRegistry();
SessionFactory sessionFactory = configuration.buildSessionFactory(serviceRegistry);
Session session = sessionFactory.openSession();

Transaction transaction = session.beginTransaction();
 
Map<String,String> programingLangsMap1= new HashMap<String,String>();
programingLangsMap1.put("L1","Java");

programingLangsMap1.put("L2","Java script");

programingLangsMap1.put("L3","Python");

 

Map<String,String> programingLangMap2= new HashMap<String,String> ();

programingLangMap2.put("L1","Kotlin");

programingLangMap2.put("L2","Type Script");

programingLangMap2.put("L3","Scala");

 

PolyglotProgramer developerJK = new PolyglotProgramer ();
developerJK.setDeveloperId("1");

developerJK.setDeveloperName("Johny Kumar");

developerJK.setCompanyName("SpaceX");

developerJK.setProgramingLanguages(programingLangMap1);

PolyglotProgramer developerRAM = new PolyglotProgramer ();
developerRAM.setDeveloperId("2");

developerRAM.setDeveloperName("Ram");

developerRAM.setCompanyName("Tesla");

developerRAM.setProgramingLanguages(programingLangMap2);
 
session.persist(developerJK);

session.persist(developerRAM);
 
transaction.commit();

session.flush();
session.close();
System.out.println("Saved.............");
}
}

 

Hibernate.cgf.xml

<?xml version = "1.0" encoding = "utf-8"?>

<!DOCTYPE hibernate-configuration SYSTEM

"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">

<hibernate-configuration>

<session-factory>

 

<property name="hibernate.show_sql">true</property>

<property name="hbm2ddl.auto">update</property>
<property name="hibernate.dialect">org.hibernate.dialect.ProgressDialect</property>
<property name="hibernate.connection.driver_class">org.postgresql.Driver</property>
 
<!-- Assume hibernate is the database name -->
 
<property name="hibernate.connection.url">jdbc:postgresql://localhost/hibernate</property>
<property name="hibernate.connection.username">postgres</property>
<property name="hibernate.connection.password">postgres</property>

<mapping class="in.jk.map.maping.PolyglotProgramer" />

</session-factory>

</hibernate-configuration>

 

 

In Database table data look like this ...........

polyglot_programer_map table data



programing_langs_map table data